Question

what are the factors of the following trinomial ? 12g^2 + 42g -24

Answer 1

maybe easiest to factor out a 6 first and write
\[6(2g^2+7g-4)\]

Answer 2

the rest factors as
\[(x+4)(2x-1)\]

Answer 3

first simplify by dividing by 6
so it becomes
6(2g^2 + 7g - 4)
now factorize whats in the brackets
6( 2g )(g )
now we need to fill in the 2 blanks to give
the final answer
these are
-1 and + 4

6 (2g - 1)(g + 4)

Answer 4

MY CHOICES ARE A (6g-3) (2g +8) B (2g-3) (6g+8) C (6g +3) (2g-8) D (2G+3) (6G-8)