multiply and simplify: (7-radical 3) (9-radical 12)
shadow that isnt right.
oh i thought he was trying to say * not subtract....
63 - 6 -9rad3 -7rad12 = 30 - 9rad3 -14rad3 = 30 - 23rad3
\[(7-\sqrt{3})(9-2\sqrt{3})\] is a start
sorry its 57 - 23rad3
then do the 4 necessary multiplications and you will get it.
\[7\times 9 -7\times 2\sqrt{3}-9\times \sqrt{3}+2\sqrt{3}\times \sqrt{3}\]
\[7*9-7*\sqrt{12}-\sqrt{3}*9+\sqrt{3}\sqrt{12}=63-7\sqrt{12}-9\sqrt{3}+\sqrt{36}\] =\[63-7*\sqrt{3*4}-9\sqrt{3}+6=63-6-7\sqrt{4}\sqrt{3}-9\sqrt{3}=57-7*2\sqrt{3}-9\sqrt{3}\] =\[57-14\sqrt{3}-9\sqrt{3}=57-23\sqrt{3}\]
\[63-14\sqrt{3}-9\sqrt{3}+6\] \[69-23\sqrt{3}\]
lol
ok i get 69 and not 57 and i am sticking with my answer
I like that much better.
satellite is right
with all gory details worked out, but if any step is not clear let me know
jimmy and i got the same wrong answer lol
yes - its 63 + 6 not 63-6 - satellite is correct
\[\color{pink}{\text{very very sleep....}}\]
yes i probably need sleep
i'm gonna get my hours fix today i will not sleep until 8 pm
then sleep for 24 hours.
i cant
Another concensus!
i got 2 wrong answers - lol!
lol
From Mathematica:\[N\left[\left(7-\sqrt{3}\right)\left(9-\sqrt{12}\right),20\right]=29.162831425915822249 \]\[N\left[69-23 \sqrt{3},20\right]=29.162831425915822249 \]\[N\left[57-23\sqrt{3},20\right]=17.162831425915822249 \]
well whats 12 between friends
yes i already seen my mistake for some reason i did 63-6 when we had 63+6
yeah well i looked at 63 and made it 36 (dyxlexia???}
yes i blame it on that too
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