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OpenStudy (anonymous):
the perimeter of a retangle room is 166ft, find the length and width of the room if the length is 5 ft longer than twice the width
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myininaya (myininaya):
2L+2W=166 L=5+2W
myininaya (myininaya):
2(5+2W)+2W=166 10+4W+2W=166 10+6W=166 6W=156 W=156/6
OpenStudy (anonymous):
let wifth = x then the length = 2x + 5 so 2(2x+5) + 2x = 166 solve for x and you have it
OpenStudy (anonymous):
are u ok with these answers ?
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