Question

4x^3 - 3x^2 + x + 1 divided by x^2 + 3
how to divide using long division form

Answer 1

first 4x times:
\[4x^{3}-3x^{2}+x+1-4x^{3}-12x=-3x^{2}-11x+1\]
-3 times:
\[-3x^{2}-11x+1+3x^{2}+9=-11x+10\]
so we get 4x-3 with remainder -11x+10

Answer 2

4x - 3
___________________________
x^2 + 3 | 4x^3 - 3x^2 + x + 1
-------- -4x^3 - 12x
-----------------------
- 3x^2 - 11x + 1
3x^2 + 9
-----------------
- 11x + 10

so quotient = 4x -3
remainder = -11x + 10