Question

the perimeter of a retangular room is 166ft.find the length and width of the room if the length is 5 ft longer than twice the width.

Answer 1

26x57

Answer 2

P = 2w + 2l
166 = 2w + 2(2w+5)
166 = 6w + 10
156 = 6w
26 = w
52 + 5 = 57 = l

Answer 3

let the width be =w
length=2(w+5)
166=2w+2(2w+5)
166=2w+4w+10
156=6w
w=26
l=2(26)+5
57