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the perimeter of a retangular room is 166ft.find the length and width of the room if the length is 5 ft longer than twice the width.
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26x57
P = 2w + 2l 166 = 2w + 2(2w+5) 166 = 6w + 10 156 = 6w 26 = w 52 + 5 = 57 = l
let the width be =w length=2(w+5) 166=2w+2(2w+5) 166=2w+4w+10 156=6w w=26 l=2(26)+5 57
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