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Mathematics 15 Online
OpenStudy (anonymous):

The length of a rectangle is fixed at 21 cm. What widths will make the perimeter greater than 82cm?

OpenStudy (anonymous):

P > 82 cm P = 2l + 2w 2l +2w > 82 cm 2(21 cm) + 2w > 82 cm 42 cm + 2w > 82 cm 2w > 40 cm w > 20 cm ANSWER: width > 20 cm

OpenStudy (anonymous):

2x + 42 > 82 [2x represents the width, 42 the two lengths] 2x > 40 x > 20

OpenStudy (anonymous):

2w+2l>82 2w+42>82 2w>40 w>20 the widths that will make the perimeter >82 is when w>20

OpenStudy (anonymous):

do I need to include the > sign with the answer

OpenStudy (anonymous):

Definitely!

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