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Evaluate the expression and write the result in the form a + bi. 8i(1/8 − i)
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\[8i (1/8 - i) = i - 8i^2 = i - 8(-1) = i +8\]
or 8 + 1i
i wonder what form my prof expects it in
a+ bi form would be 8 + i
put the one in from just in case I guess
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so just put: 8 + 1i
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