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OpenStudy (anonymous):
Solve [\dy/dx=(-5x+y)^2 -4]\ I got [\ln1/6((u-3)/(u+3))=x]\ using a substitution of u=(-5x+y). Is that right?
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OpenStudy (anonymous):
Sorry about the equation, it got butchered
OpenStudy (anonymous):
\[dy/dx=(-5x+y)^2 -4\]
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