Question

solve

-11≤3x+1 and 3x+1>13

Answer 1

\[-11\leq 3x+1\]
\[-12\leq 3x\]
\[-4\leq x\] is the first one.

Answer 2

\[3x+1\geq 13\]
\[3x\geq 12\]
\[x\geq 4\] is the second

Answer 3

now if it really says solve

-11≤3x+1 AND 3x+1>13

there is no solution since there is nothing that is both bigger then 4 and at the same time less than -4

if it says

11≤3x+1 OR 3x+1>13

then the solution is
\[(-\infty,-4)\cup (4,\infty)\]