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OpenStudy (anonymous):
the perimeter of a rectangle is 156 inches the length exceeds the width by 18 inches find the length and width find the lenght and width
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OpenStudy (anonymous):
perimeter = 2x + 2y (where x and y are length and width respectively). thus x=y+18, so we have 156=2x+2y = 2(y+18) + 2y... solve for the value of y
OpenStudy (anonymous):
30 and 48
OpenStudy (anonymous):
once you have the value of y (the width) from the method i told you, then add 18 to get the length. and 30 and 48 are wrong...
OpenStudy (anonymous):
ignore that last part bward, i just brainfarted, those are definitely the right numbers
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