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Find all solutions of the equation and express them in the form a + bi. x2 − 10x + 26 = 0 x=________ (positive imaginary) y=________ (negative imaginary)
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apply the quadratic formula
y ?
(x-5)^2 +1 =0
oh
your esp is better than mine
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lol
x=5+-i
x=5+i , x=5-i
wait , didnt read lol
one is for +1 and one is for -1
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\[x^2-10x=-26\] \[x^2-10x+25=+25-26\] \[(x-5)^2=-1\]\[(x-5)=\pm i\] \[x=5 \pm i\]
still seems like a bit of a stupid question
"positive" and "negative" imaginary
agreed
i dont understand what they are asking really
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x=1, y=-1 its pretty stupid
i typed it wrong i just realized its x and x
and its asking for the positive and negative imaginary part
does that make sense
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