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Mathematics 9 Online
OpenStudy (anonymous):

solve for x. y = Ae^kx

OpenStudy (anonymous):

y/A = e^kx apply natural log on both sides ln(y/A) = kx ln y - ln A = kx x = (ln y - ln A)/k

OpenStudy (anonymous):

or try \[\frac{y}{A}=e^{kx}\] \[\ln(\frac{y}{A})=kx\] \[x=\frac{\ln(\frac{y}{A})}{k}\]

OpenStudy (anonymous):

same answer

OpenStudy (anonymous):

This doesn't look right. Isn't A a matrix?

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