Question

solve the compound inequality
7>-2x+6 or 10 less than or equal to -2x+3

Answer 1

eqn 1.\[7>-2x+6\]
x>-1/2 .....(1)

eqn 2.
\[10 \le -2x+3\]
\[x \le-7/2\].....(2)
\[x=(-\infty,-7/2]\cup(-1/2,\infty)\]

Answer 2

\[-{1\over2}<x \le-{7\over2}\]