Question

solve using the elimination method: 5r-8s=-25 8r+5s=49

Answer 1

it seems if you try to cancel out one variable it ends up cancelling out the other one as well
this means there are no solutions for this system of equations

Answer 2

5r - 8s = -25 -----------(1)
8r + 5s = 49 -----------(2)

Multiply (1) by 8 and (2) by 5

40r - 64s = - 200 --------(3)
40r + 25s = 245 --------(4)

subtracting (4) from (1), we get
-89s = - 445
s = -445/-89
s = 5

substitute s = 5 in (1)
5r - 8(5) = -25
5r - 40 = -25
5r = -25 + 40
5r = 15
r = 15/5
r = 3

so solution set = (3,5)

Answer 3

so jm92 was wrong........

this pair of linear equations has a solution

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