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A rectangular playground has a perimeter of 60m and an area of 216m^2. Find the dimensions of the playground. Thanks :)
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2(l+b)=60 l*b=216
2l+2b=60 2l=60-2b l=30-b
he's on the way yes?
\[(30-b)b=216\] \[30b-b^2=216\] \[b^2-30b+216=0\] \[(b-18)(b-12)=0\] \[b=18\] or \[b=12\]
so i am willing to be one side is 12 and the other is 18
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check is easy enough, \[18\times 12=216\] and \[18+12+18+12=60\]
(2a+2b)=60 ab=216 a=216/b 2(216/b)+2b=60 b=18 or 12 substitute to find a a*18=216 a=12 a*12=216 a=18 the sides are 18 and 12
thank u very much :) rly appreciated ur help!
satellite, isn't 30b-b^2=216 equal to.. b^2 - 30b - 216 = 0 and not b^2 - 30b + 216 = 0 why must we add 216?
do any of u know why? ):
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