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write the equation fo the line through(6,4) that is perpendicular to y = 1/3x - 2?
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what is an important property of perp lines?
y = -3x + 22
The clue here will be the line will have an equation y = mx + c, where m is the negative reciprocal of the line y =1/3x -2. then just plug in the values of x= 6 and y=4 to obtain c.
i m getting y = 1/3x +2?
y-4=-3(x-6) y-4=-3x+18 y=-3x+22
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y = mx -mPx +Py
since perp lines have flipped slopes ... and swapped signs; 1/3 becomes -3 y = -3x -(-3)(6) + 4
thx
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