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get the y" of this please y = sqr. (1-4x)^3
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y = sqr. (1-4x)^3\[y = \sqrt{1-4x)^3}\]
3/2(1-4x)^1/2 (-4)
\[y ^{'}=-6\sqrt{1-4x}\] \[y ^{''}=12/\sqrt{1-4x}\]
Based on:\[y=\sqrt{(1-4x)^{3}}=(1-4x)^{3/2}\]
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