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Solve the following system of equations. 2x – y + z = –3 2x + 2y + 3z = 2 3x – 3y – z = –4 Answer (1, 3, –2) (1, 3, 2) (1, –3, 2) (–1, 3, 2)
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do u guys know
jus put in the values nd check which one satisfies equation if u want it to be quick .... else subtact =n 1 & 2 ... x will b eliminated frm 1 .. x=( y-z-3)/2 put in 3 nd solve the linear equations in y nd z find y nd z put in 1 nd get x :)
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