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evaluate the expression and write the result in the form a + bi. (5 + 3i)(2 − i) over/3 + i
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10 - 5i + 6i -3i^2 = 10 + i + 3 = 13 + i.
:^)
(5+3i)(2-i)= 10-5i+6i+3 = 13 + i (13+i)/ (3+i)= 4-i
so wait which one is it?
4- i
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I got the numerator. The whole problem is now reduced to (13 + i)/(3 + i).
= (13 + i)(3 - i)/[3 + i)(3 = i)]
= (39 - 13i + 3i - i^2)/10 (40 - 10i)/10 4 - i.
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