Question

In a right triangle ABC, the legs are AB = 5 and BC = 12, and in the right triangle DEF, the hypotenuse is DE = 10, and EF = 8. Which is DF + AC?
Answer

19

15

13

12

Answer 1

In a right angle triangle
Hypotenuse^2=Base^2+Altitude^2
AC^2=5^2+12^2=169=13^2
AC=13
DE^2=EF^2+DF^2
DF^2=DE^2-EF^2=100-64=36
DF=6

AC+DF=13+6=19