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In triangle ABC, D is midpoint of AB, E is midpoint of AC, and F is midpoint of BC. Prove segment AF and segment DE bisect each other. (note: you may need other segments).
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Any ideas how to set this up in the general case for any triangle.
This seems straightforward enough, for X point of intersection, ADE similar ABC -> DX = XE = BC/2 -> AF bisects DE AND by the same reasoning AX = XF so DE bisects AF.
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