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OpenStudy (anonymous):
Determine steady-state value of the current I-2(see attachment)
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OpenStudy (anonymous):
OpenStudy (anonymous):
is it 0.25 A??
OpenStudy (anonymous):
the capacitor behaves like a broken wire and the inductor as a plain wire
OpenStudy (anonymous):
someone reply?????
OpenStudy (anonymous):
I do have option ,that I-2=3,12,2,4 or 0 A. Thanks.
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OpenStudy (anonymous):
then i have no idea....i thought of equating the flux linkage bt m getting nowhere frm there
OpenStudy (anonymous):
Thank you for you time !!!!
OpenStudy (anonymous):
4
OpenStudy (anonymous):
Thank you!!!!
OpenStudy (anonymous):
shall i explain??
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OpenStudy (anonymous):
just divide the voltage by resistance
OpenStudy (anonymous):
O.K.Thank you.
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