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Mathematics 21 Online
OpenStudy (anonymous):

Determine steady-state value of the current I-2(see attachment)

OpenStudy (anonymous):

OpenStudy (anonymous):

is it 0.25 A??

OpenStudy (anonymous):

the capacitor behaves like a broken wire and the inductor as a plain wire

OpenStudy (anonymous):

someone reply?????

OpenStudy (anonymous):

I do have option ,that I-2=3,12,2,4 or 0 A. Thanks.

OpenStudy (anonymous):

then i have no idea....i thought of equating the flux linkage bt m getting nowhere frm there

OpenStudy (anonymous):

Thank you for you time !!!!

OpenStudy (anonymous):

4

OpenStudy (anonymous):

Thank you!!!!

OpenStudy (anonymous):

shall i explain??

OpenStudy (anonymous):

just divide the voltage by resistance

OpenStudy (anonymous):

O.K.Thank you.

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