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for the given functions f ang g find the following. For parts (a)-(d),also find the domain *Given f(x)=1/x and (f/g)(x)=x+1/x^2-x find the function g.
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that was close. just upside down i think
oops where did it go?
haha I thought it was upside down too. g(x) = (x - 1) / (x + 1)
ok should i rewrite the problem
\[(f/g)(x)=\frac{x+1}{x^2-x}=\frac{x+1}{x(x-1)}=\frac{1}{x}*\frac{x+1}{x-1}\] \[=\frac{1}{x} \div \frac{x-1}{x+1}=f \div g\]
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do you see what g is?
domain of f, all real numbers except 0. range all number except 0
domain of g all numbers except -1 range all numbers except 1
ooo ok im trying to figure it out thanks you guyz
yw from myininaya
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yes look what i wrote is it obvious what g is?
o duh yes lol
go to sleep satellite
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