Two planes, which are 3800 miles apart, fly toward each other. Their speeds differ by 50 mph. If they pass each other in 4 hours, what is the speed of each?

Question

anonymous · Answer

Plane 1 is traveling at 450 MPH
Plane 2 is traveling at 500 MPH

anonymous · Answer

4R + 4(R+50) = 3800

anonymous · Answer

Let R = the speed traveled by Plane 1.

anonymous · Answer

Apply the distance forumla: d=rt
.
Let x = faster plane
then
x-50 = slower plane
.
4x + 4(x-50) = 3800
Dividing both sides by 3:
4x + 4x-200 = 3800
                  8x = 3800+200
                    x = 4.000/8
x = 500 mph (faster plane)
.
Slower plane:
x-50 = 500-50 = 450 mph

anonymous · Answer

Thank ya'll