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OpenStudy (anonymous):
x squared = 5x minus 6 solve for x solve and explain please
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OpenStudy (anonymous):
x^2=5x-6 x^2-5x+6=0 (x-2)(x-3)=0 x=2 x=3
OpenStudy (anonymous):
x^2 = 5x - 6 move all variables so equation = 0 undo the foil and (x-2)(x-3) =0
OpenStudy (anonymous):
so x=2 or x =3 both real answers
OpenStudy (anonymous):
mistype on 6
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