Question

solve for x: x ^{4}-13x ^{2}+36=0

Answer 1

Put x^4 as t^2....And then Solve... :) Good LUck

Answer 2

x ^{4}-13x ^{2}+36=0 is a quadratic equation in disguise. Very sneaky!

Answer 3

Let x^2 = n

Now you have n^{2}-13x n+36=0

now try it

Answer 4

oh dont for get 36 = 6^2

Answer 5

?

Answer 6

take t=x^2
t^2 - 4t- 9t + 36 =0
t (t -4) - 9(t-4) =0
therefore t= 9,4

Answer 7

Sorry let me be clear

...oh well mridul beat me to it