Question

Find the area of an equilateral triangle (regular 3-gon) with the given measurement.

9-inch perimeter

A = sq. in.

Answer 1

\[A=\frac{\sqrt3 a^2}{4}\]
perimeter=3a=9
a=3
\[area,A=\frac{9\sqrt3}{4}sq inch\]
=3.897 sq inch