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How do I complete the following distributive property/combining like terms problems? 1) 2(x + 3)= 2) 15y-6y= 3) 3x-(-9x)= 4) 9y-6+5y= 5) -4n+3(2+n)= 6) 10n-7+6(n+5)= 7) (5) (-2)-3= 8) -11y+2(y-3)=
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1)2x+6 2)9y 3)12x 4)4y-6=2(2y-3) 5)3-n 6)4n-23 7)30 8)-3(3y-2)
oops sorry i made small mistake... 8)-3(y+2)
can you explain number 4 and number 5?
yep...in number 4 5y is subtracted by 9y which gives 4y...and according to question it becomes 4y-6 and if we take 2 as common then we get answer 2(2y-3)
-4n+6+3n(cause as given in question 3 is multiplies with 2 and n) and again 3n is subtracted by 4n so the answer become (6-n)
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