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I'm having trouble with order of operations. Solve each the following equation for x: 2x=-2[5-2(2x-12)]
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alright here we go...
lmao it's probably something simply i'm missing
i got half off on a test for missing order of operations...
i distributed the -2 to the 2x and -12 first...
i got 2x=-10-4x+24 first. which i guess is wrong. lol
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2x=-2[5-2(2x-12)] 2x=-2[5-4x+24] 2x=-2(-4x+29) 2x=8x-58 58=6x x=58/6
ohhhhhhhhh. wow
angela is way faster at typing than me lol but hers is correct
haha. thank you guys... i seemed to have not been taught this integral part in my lower level classes. :(
:)
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it won't let me select correct answer for some reason. can you guys hook each other up with one? thanks again!!!
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