I'm having trouble with order of operations.
Solve each the following equation for x:
2x=-2[5-2(2x-12)]

Question

anonymous · Answer

alright here we go...

anonymous · Answer

lmao
it's probably something simply i'm missing

anonymous · Answer

i got half off on a test for missing order of operations...

anonymous · Answer

i distributed the -2 to the 2x and -12 first...

anonymous · Answer

i got 2x=-10-4x+24 first. which i guess is wrong. lol

angela210793 · Answer

2x=-2[5-2(2x-12)]
2x=-2[5-4x+24]
2x=-2(-4x+29)
2x=8x-58
58=6x
x=58/6

anonymous · Answer

ohhhhhhhhh. wow

anonymous · Answer

angela is way faster at typing than me lol but hers is correct

anonymous · Answer

haha. thank you guys... i seemed to have not been taught this integral part in my lower level classes. :(

angela210793 · Answer

:)

anonymous · Answer

it won't let me select correct answer for some reason. can you guys hook each other up with one? thanks again!!!