Question

really comfused with the acts. Check it out please.
(conjugate of z)*w=2+3x+(2x-3)i
and (conjugate of w)*z=2+3x-(2x-3)i
Find x when you know this :[(conjugate of z)*w-(conjugate of w)*z]/(2*i)=5*[(conjugate of z)*w+(conjugate of w)*z]/2

Answer 1

now when you say (conjugate of z)*w you mean 2+3x+(2x-3)i correct?
so in the actual question you just replace the word with the equation am i getting that correct?

Answer 2

yes

Answer 3

okay give me a sec and ill work through it for you

Answer 4

thanks,I am waiting,step by step please cause I lose it for some reason. :/

Answer 5

Start with the right side
\[5(2+3x+(2x-3)i)+(2+3x-(2x-3)i)\]/2
\[10+15x+(10x-15)i+10+15x-(10x-15)i\]
\[(20+30x)/2\]

left side
\[2+3x+(2x-3)i-(2+3x-(2x-3)i)\]
\[[(2x-3)i+(2x-3)i]/[2i]\]

in total we then have
\[[(2x-3)i+(2x-3)i]/[2i] = (20+30x)/2\]

Answer 6

now are you trying to solve for x? or just simplyfy

Answer 7

I found it,thanks a lot.