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solve 3/4(2x-2)>15
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x>11
would you like some steps?
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3/4(2x-2)>15 3/4*2(x-1)>15 3/2(x-1)>15 3(x-1)>30 (x-1)>10 x>11
that is one way. here is another
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yes please ty
\[\frac{3}{4}(2x-2)>15\] \[2x-2>15\times \frac{4}{3}=5 \times 4 = 20\] \[2-2>20\] \[2x>22\] \[x>11\]
steps were 1) multiply both sides by 3/4 2) arithmetic on right hand side 3) add 2 to both sides 3) divide by 2
excuse me i mean step one was "multiply both sides by 4/3"
can u help me with a couple more please
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