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|x - 5| = 3
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x=2,8
x - 5 = 3 or x - 5 = -3. Solve from there.
The trick is to think of absolute value piece-wise
man i can't verify that inner product can u go on my question? I will finish up here..
ok
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|x-5|=3 x-5 = 3 or x-5 = -3 since abs value is always positive. Therefore: x = 3 + 5 = 8 x = - 3 +5 = 2
That's how everybody was solving it..
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