Question

I need someone good at math Please tell me how to factor to solve: (2x-3)(3x+2)≤ 0. The answer to this equation is (-2/3) ≤ x ≤ (3/2)

Answer 1

okay but the other side is whats tricky

Answer 2

how can u you just randomly split the multiplication problem into two equations like thiat?

Answer 3

plus thats wrong and does not match me answer!!! wow no one know show to do this1

Answer 4

\[(2x-3)(3x+2) \leq 0\]
\[(2x-3)= 0\]
\[(2x)= 3\]
\[(x)= 3/2\]

\[(3x+2)= 0\]
\[(3x)= -2\]
\[(x)= -2/3\]


We have to check a points less than -2/3, a points between -2/3 and 3/2 and finally a points bigger than 3/2

Answer 5

Randomly check x=
-1
0
2