Question

I need someone good at math Please tell me how to factor to solve: (2x-3)(3x+2)≤ 0. The answer to this equation is (-2/3) ≤ x ≤ (3/2)

Answer 1

\(3x+2 \leq 0\) gives \(x \leq -2/3\)

Answer 2

draw a table - 3 cols one for x<=-2/3, (-2/3) ≤ x ≤ (3/2) and x>=3/2
and a row each for
2x-3
3x+2
(2x-3)(3x+2)

and find the sign after plugging in appropriate value
you'll find that middle column will be neagative for bottom row