Mathematics
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OpenStudy (anonymous):
simplify
4rad3+7rad3-2rad3
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OpenStudy (anonymous):
9rad3
OpenStudy (anonymous):
how about 2rad3+rad12
OpenStudy (anonymous):
4rad3
OpenStudy (anonymous):
throw in as many as u want
OpenStudy (anonymous):
3rad8+7rad2
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OpenStudy (anonymous):
13rad2
OpenStudy (anonymous):
9rad4-12rad4
OpenStudy (anonymous):
-6
OpenStudy (anonymous):
+6 what
OpenStudy (anonymous):
-6
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OpenStudy (anonymous):
rad12
OpenStudy (anonymous):
2rad3
OpenStudy (anonymous):
ar u done?
OpenStudy (anonymous):
nope
OpenStudy (anonymous):
\[4 \sqrt{3}+7 \sqrt{3}-2 \sqrt{3}=9 \sqrt{3} \]Factor out the rad 3 and add up the integers. @Ishaan94 was the first to post the result.
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OpenStudy (anonymous):
rad5+4rad5
OpenStudy (anonymous):
5rad5
OpenStudy (anonymous):
u can do em on ur own
OpenStudy (anonymous):
kinda
OpenStudy (anonymous):
so y r u asking these?
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OpenStudy (anonymous):
cuz i did the work im just checking if there right
OpenStudy (anonymous):
u don't need such method to check....
OpenStudy (anonymous):
u gotta be confident on ur answers ... u aint getting solutions for every problem
OpenStudy (anonymous):
ur right
OpenStudy (anonymous):
so r u going to stop these things?
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OpenStudy (anonymous):
i will
OpenStudy (anonymous):
ask only the ones which r difficult... and try understand method.. i'l help you I promise
OpenStudy (anonymous):
so tell me the most difficult ones
OpenStudy (anonymous):
ok this problem i suck at 8rad3-rad48 im lost , i dont like math
OpenStudy (anonymous):
would it be 8 three times
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OpenStudy (anonymous):
Its Okay, Tons of ppl don't like Maths
Now To The Problem
8rad3 - rad 6x8
8rad3 - 4rad 3 ; 6= 2x3 ; 8 = 2x2x2
rad3(8-4)
4rad3
OpenStudy (anonymous):
wow
OpenStudy (anonymous):
yeah wow
OpenStudy (anonymous):
6*8 equal 48
OpenStudy (anonymous):
yes :)
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OpenStudy (anonymous):
how did you get 4rad 3
OpenStudy (anonymous):
rad ( 48)
rad(2x2x2x2x3)
--------
^
|
see these 2x2x2x2 these come out as 2x2 =4
so in problem
rad3(8-4)
4rad3
OpenStudy (anonymous):
oo okay gotcha
OpenStudy (anonymous):
Nice :)
OpenStudy (anonymous):
thank you so much for taking the time :)
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OpenStudy (anonymous):
Pleasure's Myne