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Solve p(x)=x4 + 81x2 in comma seperated list
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p(x)=x^4 + 81x^2 p(x)=t^2 + 81t, t = x^2 solve using quadratic rules.
\[P(x)=x ^{4 }+81x ^{2}\]
exactly.
is that what they consider factor p completely...man I should have paid more attention
p(x)=x^4 + 81x^2 p(x)=t^2 + 81t, t = x^2 p(x)=t(t+81) t=0, t=-81 x^2=0, x^2=-81 x^2=0, no other solutions.
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x=0 is the answer to p(x) = 0
did i do this one right then...\[p(x)=x ^{4}+6x ^{2}+9\]
i got \[(x ^{2}+3)(x ^{2}+3)\]
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