Question

(6x+1)^2 +8(6x+1) + 16=0
Help me lol..

Answer 1

u=6x+1
u^2=(6x+1)^2

\[u^2+8u+16=0\]
\[(u+4)(u+4)=0\]
\[(u+4)^2=0\]
\[u+4=0\]
\[u=-4\]
but remember u=6x+1
so
6x+1=-4
6x=-4-1
6x=-5
x=-5/6

Answer 2

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Answer 3

:)

Answer 4

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