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Mathematics 20 Online
OpenStudy (anonymous):

2w^2+11w+5 factor

jhonyy9 (jhonyy9):

(2w+1)(w+5)=2w^2 +10w +w +5 =2w^2 +11w +5

OpenStudy (anonymous):

Easy way: 1) Find roots of 2w^2+11w+5 = 0 => w1 = -½, w2 = -5 2) Answer is: 2(w-w1)(w-w2) <=> 2(w+½)(w+5) <=> (2w+1)(w+5) Hard way: 2w^2+11w+5 = 2w^2+w+10w+5 = (2w+1)(w+5)

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