hi, im trying to solve the problem of finding the 1000th prime, and have written this code:
x=2
n=0
i = range (2,9999,1)
while (n

Question

hi, im trying to solve the problem of finding the 1000th prime, and have written this code:
x=2
n=0
i = range (2,9999,1)
while (n<=1000):
    if x%i == 0 and x == i:
        print i
    x=x+1
    
n=n+1
can someone plz tell me why this is not working? (i am all new to programming) :)

anonymous · Answer

what is not working?

anonymous · Answer

a few things to note, 
1) use Dpaste.com, it works better
2) range has optional arguments, if your say range(2,9999) it'll work just fine, most of the time i just do something like range(10) if i just want a quick test run of 10
3) range produces a list with the endpoints (x,y-1), your variable i = [2,3,4,5,6,...9998]
you want a for loop for something like that
for i in range(2,10000):
    x % i == 0
i don't suggest using a for loop here

otherwise if you don't know
if
elif
else
are useful, many people miss the elif

hopefully thats enough for now

anonymous · Answer

try these resources: http://wiki.python.org/moin/BeginnersGuide http://wiki.python.org/moin/BeginnersGuide/NonProgrammers

anonymous · Answer

I'm also new at programming, and trying to work through this problem. This question will probably sound dumb, but I was confused as to how  n = 0 but at the same time n <=1000. If n =0 , wouldn't that make it definite?

anonymous · Answer

n <= 1000 is an expression that evaluates to either True or False

so if n = 0 then n <= 1000 is True