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-1 <= x -1 <= 2x+1
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\[x \ge0\]
i figured can u explain it to me
well x-1 is greater than or equal to -1 at (0,infinity) and 2x-1 is greater than or equal to x-1 at (-2,infinity) so its just where both parts are true which is (0,infinity) so pretty much split the whole thing up as -1</=x-1 and x-1</=2x+1 solve both and c where they have similar answers
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