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9x to the 4th power minus 37x squared plus 4=0 please help
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\[9x^4-37x^2+4=0\]?
yup!
ok trick is to put \[z=x^2\] and rewrite as \[9z^2-37z+4=0\] which by some miracle factors as \[(9z-1)(z-4)=0\] so \[z=\frac{1}{9}\] or \[z=4\]
then go back and put \[z^2=\frac{1}{9}\] so \[x=\pm\frac{1}{3}\] or \[x^2=4\] so \[x=\pm 2\] and those are your 4 answers.
yup!
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Amazing thank you very much !
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