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Mathematics 21 Online
OpenStudy (anonymous):

3x/x+1 (minus) 5/x

OpenStudy (anonymous):

\[\frac{3x}{x-1}-\frac{5}{x}=\frac{3x\times x-5\times (x+1)}{x(x+1)}\] \[=\frac{3x^2-5x+5}{x(x+1)}\]

OpenStudy (anonymous):

\[(3x^2-5x-5)/(x^2+x)\]

OpenStudy (anonymous):

my answer is wrong. it is \[\frac{3x^3-5x-5}{x(x+1)}\]

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