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Which of the following equations can be used to find a women's present age if she is now 6 times as old as her son and next year her age will be equal to the square of her son's age? A) 6w+1 = w^2 +1 B) 6(w+1)=w^2+1 C) 6(w+1)=(w+1)^2 D) 6w+1= (w+1)^2 E) w+6 = (w+1) ^2
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Let's say that her son is w years old right now. This means next year he will be w+1 years old. The mother is 6w this year, which means she will be 6w+1. Next year she will also be the square of her son's age. Her son's age next year will be w+1, so we have \[6w+1=(w+1)^2\]
Ohh ok. Thank you!
No problem :)
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