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file:///C:/Users/Sundus/Desktop/bs/BSE/Section_2/Q16.htm
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can you repost the link? :)
That's a link to a file on your computer....
there is a figure in which the diameter is 12cm and we have to find the area of the shaded region.figure is on this link---> http://www.twiddla.com/573294
The shaded regions are 45/45/90 triangles and the formula for triangle area is bh/2 and you have 2 of them so you want bh and bas and height are the same so you want b or h squared. So let's take BO = 6 Cos 45 (135+45=180) = 6/sqrt 2 squared = 18 (check it).
thankyou,that was right :)
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