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Mathematics 8 Online
OpenStudy (anonymous):

x^3 +3x^2 -8x-24 factor by grouping

OpenStudy (anonymous):

plshpme do u want to know how to solve this

OpenStudy (anonymous):

(x+3)*(x^2-8)

OpenStudy (saifoo.khan):

x^2(x + 3) -8(x + 3) (x^2 - 8) (x+3)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thank you guys!

OpenStudy (anonymous):

Saif...how long will you be on? I will be back in about 30 minutes.

OpenStudy (saifoo.khan):

I just woke up!

OpenStudy (anonymous):

so you will be on awhile!

OpenStudy (saifoo.khan):

Oh Yes. i think, untill my parents reach home, lol.

OpenStudy (anonymous):

ok I will be back then!

OpenStudy (anonymous):

I can Help u ! :)

OpenStudy (saifoo.khan):

Ook,

OpenStudy (anonymous):

x^3 + 3x^2 -8x -24 Now the equation is in cubic form...Have u solved them bfore?

OpenStudy (anonymous):

Now U can see Frm the Eq Taking x^2 common out of x^3 +3x^2 ... x^2(3 + x)

OpenStudy (anonymous):

And Taking -8 common out of -8x -24 -8(x + 3)

OpenStudy (anonymous):

Now The Equation becomes x^2(x + 3) - 8(x + 3) So taking (x + 3) common (x+3)(x^2 - 8) Remmbr Ur Task during Factorizing is to divide Eq. into smallest part possible.

OpenStudy (anonymous):

I Hope it was Helpful to You :)

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