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OpenStudy (anonymous):
plshpme do u want to know how to solve this
OpenStudy (anonymous):
(x+3)*(x^2-8)
OpenStudy (saifoo.khan):
x^2(x + 3) -8(x + 3)
(x^2 - 8) (x+3)
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
thank you guys!
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OpenStudy (anonymous):
Saif...how long will you be on? I will be back in about 30 minutes.
OpenStudy (saifoo.khan):
I just woke up!
OpenStudy (anonymous):
so you will be on awhile!
OpenStudy (saifoo.khan):
Oh Yes.
i think, untill my parents reach home, lol.
OpenStudy (anonymous):
ok I will be back then!
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OpenStudy (anonymous):
I can Help u ! :)
OpenStudy (saifoo.khan):
Ook,
OpenStudy (anonymous):
x^3 + 3x^2 -8x -24
Now the equation is in cubic form...Have u solved them bfore?
OpenStudy (anonymous):
Now U can see
Frm the Eq
Taking x^2 common out of x^3 +3x^2 ...
x^2(3 + x)
OpenStudy (anonymous):
And Taking -8 common out of -8x -24
-8(x + 3)
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OpenStudy (anonymous):
Now The Equation becomes
x^2(x + 3) - 8(x + 3)
So taking (x + 3) common
(x+3)(x^2 - 8)
Remmbr Ur Task during Factorizing is to divide Eq. into smallest part possible.