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What value in place of the question mark makes the polynomial below a perfect square trinomial? 9x2+?x+64
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you need so square \[(3x+8)^2\] and see what the middle term would be
48?
Yeah, it's 48
\[(3x+8)(3x+8)=9x^2+3x\times 8+ 3x\times 8 + 64\] \[=3x^2+48x+64\] you got it
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