Question

Find Exponetial Form.
(5)√(7x^(-1))

Answer 1

\[\frac{5}{\sqrt{7^{-1}}}\]
Let's start by rewriting the square root as a fraction. Taking the square root of something is the same as raising it to the 1/2 power.
\[\frac{5}{(7^{-1})^\frac{1}{2}}\]
We can multiply exponents to get
\[\frac{5}{7^{\frac{-1}{2}}}\]
Next, we can make a negative exponent into a positive exponent by moving it to the top/bottom.
\[5(7^{\frac{1}{2}})\]