Question

The first term of an arithmetic sequence is 2 and the fourth term is 11. Find the sum of the first 50 terms.

Answer 1

3775

Answer 2

how did u find that number?

Answer 3

The nth number in an arithmetic sequence = a+(n-1)d where a is the first term and d is the difference

The sum of the first n numbers in an A.P. is n/2(a+nth number)

Answer 4

Get it?

Answer 5

yes thank you!

Answer 6

The sum of 50 terms = 50/2 [2a + (n-1)d]

11 = 2 + 3d
9 = 3d
9/3 = d
3 = d

sum of 50 terms = 50/2 [2a + (n-1)d] = 25[2*2 + 49*3] = 3775