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15b^2 - 19b -10 factor by grouping
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(3b-5) (5b+2)
we have Ab^2+Bb+C find two factors of A*C that multiply to be A*C and add up to be B A*C=15*(-10)=5(-30)=75(-2)=25(-6)=-25(6) B=-19=-25+6 so replace Bb=-19b with -25b+6b so we have 15b^2-25b+6b-10 now factor by grouping 5b(3b-5)+2(3b-5) (3b-5)(5b+2)
thank you guys! sorry it took so long to respond.
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