Question

-3y(2y^2-6y+7)

Answer 1

and you are supposed to distribute?

Answer 2

not sure, all the description says is how to multiply monomials by polynomials

Answer 3

multiply each term inside parenthesis with -3y

Answer 4

first one times -3y
is
-6y^3

Answer 5

-6y^3+18y^2-21y

Answer 6

how did you get that?

Answer 7

multiplying each term inside of parenthesis by -3y

Answer 8

So multiply each term separately?

Answer 9

yes

Answer 10

so that would be...\[(-3y)(2y^2)-(-3y)(6)+(-3y)(7)\]

Answer 11

oops forgot the "y" after the 6

Answer 12

yes, except for missing y

Answer 13

i noticed the missing y after i posted it

Answer 14

good job